Ask a Doubt

Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

PLease help me out!

Asked by akshitaasia | 20 Mar, 2018, 02:58: PM

Expert Answer

begin mathsize 16px style Find space equation space of space all space the space three space lines space using space two space slope space point space form. Let space straight A left parenthesis negative 1 comma space 2 right parenthesis comma space straight B left parenthesis 1 comma space 5 right parenthesis space and space straight C left parenthesis 3 comma space 4 right parenthesis Equation space of space AB fraction numerator straight y minus straight y subscript 1 over denominator straight x minus straight x subscript 1 end fraction equals fraction numerator straight y subscript 2 minus straight y subscript 1 over denominator straight x subscript 2 minus straight x subscript 1 end fraction fraction numerator straight y minus 2 over denominator straight x minus open parentheses negative 1 close parentheses end fraction equals fraction numerator 5 minus 2 over denominator 1 minus open parentheses negative 1 close parentheses end fraction fraction numerator straight y minus 2 over denominator straight x plus 1 end fraction equals 3 over 2 2 straight y minus 4 equals 3 straight x plus 3 3 straight x minus 2 straight y plus 7 equals 0 straight y equals fraction numerator 3 straight x plus 7 over denominator 2 end fraction......... left parenthesis straight i right parenthesis Similarly space you space can space find space equations space of space BC space and space AC. you space will space get straight y equals fraction numerator 11 minus straight x over denominator 2 end fraction space is space equation space of space BC......... left parenthesis ii right parenthesis straight y equals fraction numerator straight x plus 5 over denominator 2 end fraction space is space equation space of space AC......... left parenthesis iii right parenthesis Required space area equals integral subscript negative 1 end subscript superscript 1 space open parentheses fraction numerator 3 straight x plus 7 over denominator 2 end fraction close parentheses dx plus integral subscript 1 superscript 3 space open parentheses fraction numerator 11 minus straight x over denominator 2 end fraction close parentheses dx minus integral subscript negative 1 end subscript superscript 3 space open parentheses fraction numerator straight x plus 5 over denominator 2 end fraction close parentheses dx After space simplifying space we space get space 4 space square space unit space area. end style

Answered by Sneha shidid | 21 Mar, 2018, 09:37: AM

Concept Videos

Practice Test

Webinar

Pre Board Assessment

Answered Unanswered My Questions My Answers

CBSE 12-science - Maths

Please help with the solution step by step

Asked by NITISH DAS | 15 Apr, 2020, 12:13: AM

ANSWERED BY EXPERT

CBSE 12-science - Maths

Plz answer 23rd sum with easy graph

Asked by lovemaan5500 | 29 Nov, 2019, 04:18: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

What will be the answer for this question?

Asked by dineshchem108 | 05 Jul, 2019, 05:58: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

Please answer this question.

Asked by dineshchem108 | 05 Jul, 2019, 05:56: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

PLease help me out!

Asked by akshitaasia | 20 Mar, 2018, 02:58: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

What is the area bounded by the curve y = f(x), X-axis and the ordinates x = c, x = d?

Asked by Topperlearning User | 12 Aug, 2016, 11:02: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

find the area of the triangle formed by the line x + y = 3 and angle bisectors of the pair of straight lines

x squared minus y squared plus 2 y equals 1

.

Asked by Topperlearning User | 12 Aug, 2016, 11:48: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

Find the area bounded by the curve

and X-axis.

Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

Find the area enclosed by the curve

, x = 6, x = 9 and X-axis.

Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM

ANSWERED BY EXPERT

CBSE 12-science - Maths

Find the area of region bounded by

, x = 1, x = 4 and the X-axis.

Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM

ANSWERED BY EXPERT

My Class Videos Tests Plans Ask a Doubt