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CBSE Class 12-science Answered

Please answer this question.

Asked by dineshchem108 | 05 Jul, 2019, 05:56: PM

Expert Answer

y = tan x

dy/dx = sec² x

dy/dx = sec² ∏/4 = 2

begin mathsize 16px style straight A equals integral subscript 0 superscript straight pi over 4 end superscript space tanxdx space equals space 1 half log space 2 Equation space of space tangent space straight y minus 1 equals 2 open parentheses straight x minus straight pi over 4 close parentheses straight x equals straight pi over 4 minus 1 half Area space of space increment ABC equals 1 half cross times open parentheses straight pi over 4 minus open parentheses straight pi over 4 minus 1 half close parentheses close parentheses equals 1 fourth Required space area equals 1 half log space 2 minus 1 fourth end style

Answered by Sneha shidid | 08 Jul, 2019, 11:08: AM

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