CBSE Class 12-science Answered
find the area of the triangle formed by the line x + y = 3 and angle bisectors of the pair of straight lines
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![x squared minus y squared plus 2 y equals 1](http://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=234ae7ffe00f1a68bcd9eb076c9cc310.png)
Asked by Topperlearning User | 12 Aug, 2016, 23:48: PM
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![N o w space t h e space e q u a t i o n space o f space a n g l e space b i s e c t o r s space o f space t h e s e space t w o space s t r a i g h t space l i n e s space w i l l space b e space g i v e n space b y
fraction numerator x minus y plus 1 over denominator square root of 2 end fraction equals plus-or-minus fraction numerator x plus y minus 1 over denominator square root of 2 end fraction
w i t h space t h e space plus space s i g n space w e space w i l l space g e t space y equals 1
w i t h space t h e space minus space s i g n space w e space w i l l space g e t space x equals 0
s o space b i s e c t o r s space a r e space x equals 0 space a n d space y equals 1](https://images.topperlearning.com/topper/tinymce/cache/095fa2b88e9141aa8d253a0920500e50.png)
![](https://images.topperlearning.com/topper/questions/14449_002.jpg)
So, area between x + y = 3, x = 0 and y = 1 is given by
A = ![](https://images.topperlearning.com/topper/questions/14449_image004.gif)
![](https://images.topperlearning.com/topper/questions/14449_image004.gif)
Answered by | 13 Aug, 2016, 01:48: AM
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