please find the answer

Asked by harshithauk27 | 26th Aug, 2020, 07:03: PM

Expert Answer:

The object is placed at the distance of 10 cm from the concave mirror of the focal length of 15 cm
focal length of concave mirror, f = -15 cm 
object distance, u = - 10 cm 
By mirror formula, 
1 over f equals 1 over u plus 1 over v
fraction numerator 1 over denominator negative 15 end fraction equals fraction numerator 1 over denominator negative 10 end fraction plus 1 over v
1 over v equals space fraction numerator 1 over denominator negative 15 end fraction minus space open parentheses fraction numerator 1 over denominator negative 10 end fraction close parentheses space equals space fraction numerator 1 over denominator negative 15 end fraction plus 1 over 10 space equals space fraction numerator 10 minus 15 over denominator 150 end fraction equals space fraction numerator negative space 5 over denominator negative 150 end fraction
v space equals plus space 30 space c m space
T h u s comma space t h e space i m a g e space i s space f o r m e d space a t space d i s tan c e space o f space 30 space c m space
P o s i t i v e space s i g n space i n d i c a t e s space t h a t space t h e space i m a g e space i s space f o r m e d space b e h i n d space t h e space c o n c a v e space m i r r o r. space
A s space t h e space o b j e c t space i s space p l a c e d space b e t w e e n space f o c u s space a n d space p o l e space o f space c o n c a v e space m i r r o r space t h e space i m a g e space f o r m e d space i s space b e h i n d space t h e space m i r r o r. space
I n space s u c h space c a s e space t h e space i m a g e space f o r m e d space i s space v i r t u a l comma space e r e c t space a n d space m a g n i f i e d. space

Answered by Shiwani Sawant | 27th Aug, 2020, 12:58: AM