# CBSE Class 10 Physics Mirror Formulae

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- A concave mirror produces three times magnified (enlarged) real image of an object placed at 10cm in front of it . Where is the image located?
- why presently sign convention is known as new sign convention
- findthe size nature and position of image formed when an object of size 1 cm is placed at a distance of 15from a fro from a concave mirror of focal length 10cm cm from a concave mirror of focal length in centimetre from a concave mirror of
- please find the answer
- why can't we write mirror formula as f = v + u
- Is magnification =f/f-u (or) f/u-f
- In which part of mirror we will take positive and negative sign?In Concave and convex mirror
- in magnification topic numerical problem solve
- a) The image formed in front of the concave mirror is real, so m is negative, m = -3, u = -10 cm As m = -v/u or -3 = -v/-10 v = -30 cm By mirror formula, 1/f = 1/v + 1/u = 1/-30 + 1/-10 = -4/30 or f = -30/4 = -7.5 cm Radius of curvature, R = 2f = 2 x (-7.5) = 15cm a) The image formed in front of the concave mirror is real, so m is negative, m = -3, u = -10 cm As m = -v/u or -3 = -v/-10 v = -30 cm By mirror formula, 1/f = 1/v + 1/u = 1/-30 + 1/-10 = -4/30 or f = -30/4 = -7.5 cm Radius of curvature, R = 2f = 2 x (-7.5) = 15cm the above answer is wrong pls check it
- A person has a rectangular sheet of metal.He has to make cylindrical vessel whose both circular ends are closed.When he minimizes the wastage of the sheet,then what is the ratio of the wasted sheet to the utilised sheet? (1) . 1/22 (2) . 3/11 (3) . 1/11 (4) . 5/22

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