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a concave mirror has a radius of curvature of 0.4m. find the position and size of the image of an object placed 0.2m high and is placed 0.8m in front of a concave mirror.
Asked by priyanshdhiman2008 | 17 Mar, 2023, 09:17: AM
answered-by-expert Expert Answer
R = 0.4 m 
f = - 0.2 m 
v = ?
hi = ?
ho = 0.2 m  
 
u = - 0.8 m
1 over f equals 1 over v plus 1 over u fraction numerator 1 over denominator negative 0.2 end fraction equals space 1 over v plus fraction numerator 1 over denominator negative 0.8 end fraction fraction numerator 1 over denominator negative 0.2 end fraction equals 1 over v minus fraction numerator 1 over denominator 0.8 end fraction 1 over v space equals space fraction numerator 1 over denominator negative 0.2 end fraction plus fraction numerator 1 over denominator 0.8 end fraction v space equals space fraction numerator negative 0.8 over denominator 3 end fraction space... left parenthesis I m a g e space d i s tan c e right parenthesis space m space equals space fraction numerator negative v over denominator u end fraction space equals space h subscript i over h subscript o bevelled fraction numerator negative begin display style fraction numerator left parenthesis negative 0.8 right parenthesis over denominator 3 end fraction end style over denominator negative 0.8 end fraction space equals space fraction numerator h subscript i over denominator 0.2 end fraction h subscript i equals fraction numerator 0.4 over denominator 3 end fraction
 
Answered by Shiwani Sawant | 17 Mar, 2023, 06:02: PM

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