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Asked by Prashant DIGHE | 07 Jan, 2020, 22:06: PM
answered-by-expert Expert Answer
Po1 =vapour pressure of the pure solvent
p1 =Vapour pressure of the solution
X2 =Mole fraction of the solute
 
fraction numerator P to the power of o subscript 1 minus P subscript 1 over denominator P to the power of o subscript 1 end fraction equals X subscript 2 X subscript 2 space end subscript equals fraction numerator n subscript 2 over denominator n subscript 1 space end subscript plus n subscript 2 end fraction n subscript 2 space equals space n u m b e r space o f space m o l e s space o f space s o l u t e n subscript 1 space equals space n u m b e r space o f space m o l e s space o f space s o l v e n t fraction numerator P to the power of o subscript 1 minus P subscript 1 over denominator P to the power of o subscript 1 end fraction equals fraction numerator n subscript 2 over denominator n subscript 1 plus n subscript 2 end fraction X subscript 2 equals fraction numerator 1 over denominator 1 plus 2 end fraction equals 1 third X subscript 2 space i n space left parenthesis 1 right parenthesis comma space w e space g e t fraction numerator P to the power of o subscript 1 minus P subscript 1 over denominator P to the power of o subscript 1 end fraction equals 1 third P subscript 1 over P subscript 1 to the power of o equals space 2 over 3
Answered by Ravi | 08 Jan, 2020, 12:39: PM
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