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<div>The volume of an ideal gas is V at pressure P. On increasing the pressure by&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=26816d2f3387562091ce3d0b42130299.png" alt="increment P" align="middle" />, the change in volume of the gas is&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=0e068781bc829d936d54d5fffecd1d08.png" alt="increment V subscript 1" align="middle" />&nbsp;under isothermal conditions &amp;&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=03ae4ab69fed6c91e7c4c18bf63c7315.png" alt="increment V subscript 2" align="middle" />&nbsp;under adiabatic conditions. Which one is greater&nbsp;<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=ad72593b611ba84f5684c6f13ab3a7dc.png" alt="increment V subscript 1 space end subscript space o r space increment V subscript 2" align="middle" />? Explain with reason. If we open the door of a refrigerator in a closed room, the room does not get cooled. Why?</div>
Asked by bhawnanaman | 25 Apr, 2016, 06:15: AM
The refrigerator is a heat pump. It takes in the air and cools it by removing heat from it. This heat goes out in the surroundings from the back of the refrigerator. So, we are adding heat to the room thereby heating it.
Now, if we keep the door of the refrigerator open for a while, then more heat has to be removed from inside the fridge in order to cool the stuff inside. This will throw more heat out in the room thereby heating the room instead of cooling it.

NOTE: Kindly post the other question as a separate query.
Answered by Romal Bhansali | 25 Apr, 2016, 12:41: PM

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