CBSE Class 11-science Answered
Kinetic energy of an electron emitted when radiation of frequency v= 1.25 x10^15 strikes the metal surface whose threshold frequency v0 = 7.25 x 10^14 is
Asked by arushidabhade | 29 Jun, 2019, 08:42: PM
Expert Answer
Given:
K.E. = 1.25 x1015 s-1
Threshold frequency ν0 = 7.25 x 1014 s-1
Plank's constant, h = 6.62 × 10-34 m2kg/s
Energy of radiation = hν0 = h(v-ν0)
= 6.62 × 10-34 (12.51014 - 7.25 x 1014)
=3.5 x 10-19 J
Answered by Varsha | 29 Jun, 2019, 11:16: PM
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