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CBSE Class 10 Answered

In triangle abc angle b=90 bc+ab=17cm bc-ab=7cm find sin a cos c
Asked by Shaikmustafa | 13 Mar, 2019, 16:15: PM
answered-by-expert Expert Answer
Let us use the notation  side BC = a cm  ,  AB = c cm
 
Given :   c+a = 17  .................(1)
              c -a = 7  ...................(2)
 
By adding both eqn., we get  2 c = 24   or  c = 12 cm
By subtracting eqn.(2) from eqn.(1), we get   2 a = 10   or  a = 5 cm
 
Then side AC = b = begin mathsize 12px style square root of 12 squared plus 5 squared space end root space equals space 13 space c m end style
sin(A) cos(C) = (5/13)(5/13) = 25/169
Answered by Thiyagarajan K | 13 Mar, 2019, 20:56: PM

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