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CBSE Class 10 Answered

In /_\ABC right angled at B AB=24cm,BC=7cm.Determine : 1.sinA,cosA 2.sicC,CosC
Asked by chpratik11 | 07 Mar, 2020, 02:43: PM
answered-by-expert Expert Answer
In Δ ABC, right-angled at B
Using Pythagoras theorem
AC² = AB² +BC²  
AC² = 576 + 49 = 625
AC = √625
AC = 25

Now
In a right angle triangle ABC where B=90° ,
(i) Sin A = BC/AC = 7/25
    CosA = AB/AC = 24/25
(ii) Sin C = AB/AC = 24/25
     Cos C = BC/AC = 7/25
Answered by Arun | 07 Mar, 2020, 09:13: PM

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