L e t space alpha space a n d space beta space b e space s o l u t i o n s space o f space e q u a t i o n space x squared minus 6 x minus 2 equals 0 space w i t h space alpha greater than beta.
I f space bevelled fraction numerator a subscript 10 minus 2 a subscript 8 end subscript over denominator 2 a subscript 9 end fraction space i s ?

Asked by aahnik.mohanty | 10th Jun, 2019, 08:34: PM

Expert Answer:

x2 - 6x - 2 = 0
Multiplying by x8 on both sides
x10 - 6x9 - 2x8 = 0
α and β are the roots of the equation
α10 - 6α9 - 2α8 = 0  ....(i)
β10 - 6β9 - 2β8 = 0  ....(ii)
Subtracting (ii) from (i)
10 - β10) - 6(α9 - β9) - 2(α8 - β8) = 0
where a10 = α10 - β10, a9 = (α9 - β9) and a8 = (α8 - β8)
 
a10 - 6a9 - 2a8 = 0
a10  - 2a8 = 6a9
a10  - 2a8 = 3 × 2a9
(a10  - 2a8) /2a9 = 3

Answered by Sneha shidid | 11th Jun, 2019, 11:04: AM