IF TAN 25 DEGREE= A THEN TAN 205 DEGREE- TAN 115 DEGREE DIVIDED BY TAN 245 DEGREE +TAN 335 DEGREE =?

Asked by Vivek Sehgal | 2nd May, 2012, 01:56: PM

Expert Answer:

tan 25 =a
tan205°=sin205°/cos205° = sin(180° + 25°)/cos(180° + 25°)
=(?sin25°)/(?cos25°)=tan25°=a
tan 115°=tan(90°+25°) =?cot25° =?1/a
(tan 245)=sin(180°+65°)/cos(180°+65°) =(?sin65°)/(?cos65°)=cos25°/sin25° =1/a
tan 335=sin(360°?25°)/cos(360°?25°) =(?sin25°)/(cos25°)=?tan25°=?a

Hence ,
(tan 205°?tan 115°)/(tan 245°+ tan 335°) =
={a?(?1/a)}/(1/a?a) ={(a²+1)/a)}/{(1?a²)/a} =(a²+1)/(1?a²)

Answered by  | 3rd May, 2012, 10:36: AM

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