CBSE Class 11-science Answered
IF TAN 25 DEGREE= A THEN TAN 205 DEGREE- TAN 115 DEGREE DIVIDED BY TAN 245 DEGREE +TAN 335 DEGREE =?
Asked by Vivek Sehgal | 02 May, 2012, 01:56: PM
Expert Answer
tan 25 =a
tan205°=sin205°/cos205° = sin(180° + 25°)/cos(180° + 25°)
=(?sin25°)/(?cos25°)=tan25°=a
tan 115°=tan(90°+25°) =?cot25° =?1/a
(tan 245)=sin(180°+65°)/cos(180°+65°) =(?sin65°)/(?cos65°)=cos25°/sin25° =1/a
tan 335=sin(360°?25°)/cos(360°?25°) =(?sin25°)/(cos25°)=?tan25°=?a
Hence ,
(tan 205°?tan 115°)/(tan 245°+ tan 335°) =
={a?(?1/a)}/(1/a?a) ={(a²+1)/a)}/{(1?a²)/a} =(a²+1)/(1?a²)
Answered by | 03 May, 2012, 10:36: AM
Concept Videos
-
Trigonometric identities and problems
Fundamental trigonometric identities and problems based on them. Sign Conve... -
Degree measure and Radian measure ...
This video explains the concept of negative & positive angles, conversion o... -
Domain, period and range of trigonometric functions ...
Define the domain, period and range of the trigonometric functions and plot... -
Basic Trigonometric Formulae
Derive and apply the basic formulae of sine and cosine functions like sin(... -
Sign of Trigonometric Functions
This video covers values of trigonometric ratios of angles greater than 90 ...
CBSE 11-science - Maths
Asked by rajyothi64 | 05 Mar, 2024, 09:49: PM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by ghoshshawata62 | 04 Mar, 2024, 08:16: PM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by nayaktapaswini2007 | 29 Feb, 2024, 09:10: AM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by bimanmandal53361 | 15 Jan, 2024, 12:32: AM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by sreyas.katuri | 23 Sep, 2023, 07:12: AM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by 069.pks | 16 Sep, 2023, 10:06: AM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by surekhashriwas01 | 12 Sep, 2023, 08:39: PM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by mvr23467 | 12 Sep, 2023, 07:52: PM
ANSWERED BY EXPERTCBSE 11-science - Maths
Asked by SasipriyaNagappan | 27 Jul, 2023, 07:22: PM
ANSWERED BY EXPERT
