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CBSE Class 10 Answered

if sin3A=COS[A-26] WHERE 2A IS AN ACUTE ANGLES FIND THE VALUE OF A.  
Asked by ABHILASHA | 15 Jan, 2019, 03:05: PM
answered-by-expert Expert Answer
If 2A is acute angle, let us assume 3A > 90°  and let 3A = 90+θ
 
we have sin(90+θ) = cosθ  .................(1)
given eqn.:- sin(3A) = cos(A-26)..........(2)
 
by comparing eqn.(1) and (2), we get,  θ = ( A - 26 )   and 3A = 90+θ
 
hence 3A = 90+θ = 90+(A-26) = 64+A   or   2A = 64   or  A = 32
Answered by Thiyagarajan K | 15 Jan, 2019, 03:46: PM
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