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IF A HEATER WITH POWER 1000W GIVES 3.6*10^6 joules OF HEAT ENERGY IN ONE HOUR.WHAT WILL BE THE TEMPERATURE RAISED IN THE 50KG OF WATER TEMPERATURE 30 DEGREE CELCIUS BY THAT HEAT.
Asked by anish.kunwar.123 | 17 Jul, 2018, 09:11: PM
Heat required to raise the temperature of water is Q= 3.6×106 J.
Mass of water = 50 kg

We know that Q = m×c×Δt ... (1)
Rise in temperature Δt= tf - ti
A the temperature of water is 30°C,
Δt= tf - 30
Specific heat of water is 4200J/kg/°C.

From (1),

temperature of water raised due to this amount of energy is ( tf)= 47.14°C

→ Δt = 47.14°C - 30°C = 17.14°C

Thus, the rise in temperature is 17.14°C
Answered by Shiwani Sawant | 18 Jul, 2018, 12:21: PM

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