CBSE Class 11-science Answered
If a body is projected at the angle of 45degree with a velocity of 20m/sec.Find it's height reached when it covers a distance of 15m in horizontal.
Asked by surjan06singh | 13 Aug, 2019, 08:04: PM
Expert Answer
Horizontal velocity component = 20×cos45 m/s = 20×(1/√2) = 10√2 m/s
time taken t to travel 15 m is given by, t = 15/(10√2) = (3/4)√2 s
vertical distance h travelled in a time t = (3/4)√2 s is given by,
h = u×sinα×t - (1/2)g t2 = 20×sin45×(3/4)√2 -(1/2)×9.8×[(3/4)√2]2 ≈ 9.5 m
Answered by Thiyagarajan K | 13 Aug, 2019, 09:44: PM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT