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CBSE Class 10 Answered

give solution of this question
Asked by suhanirao1702 | 30 May, 2020, 10:02: PM
Expert Answer
Distance between crystalline eye lens and retina (screen) is 2.4 cm 
 
This means that focal length of the system is f =0.024 cm 
Thus, 
power of his lens system is, 
P equals space 1 over f
P space equals space fraction numerator 1 over denominator 0.024 space m space end fraction space equals space plus 41.66 space D space 
 
 While reading book is placed at 25 cm
Which means object distance, u = 25 cm = 0.25 m 
and 
Image distance is the distance between the lens and screen (image is formed)
Image will be formed on retina. So image distance, v = 2.4 cm =0.024 m 
 
By lens formula, 
1 over f equals space 1 over v minus 1 over u
u space equals space minus space 0.25 space m space left parenthesis o b j e c t space p l a c e d space t o space t h e space l e f t space s i d e space o f space t h e space l e n s right parenthesis

1 over f equals space fraction numerator 1 over denominator 0.024 end fraction minus fraction numerator 1 over denominator left parenthesis negative 0.25 right parenthesis end fraction
1 over f space equals space plus space 45.66
T h u s comma space
P space equals space 1 over f space equals space plus space 45.66 space D space a n d space f o c a l space l e n g t h space d e c r e a s e s space w h i l e space o b s e r v i n g space n e a r b y space o b j e c t s space h e r e space i n space t h i s space c a s e space t h e space o b j e c t space i s space a t space l e a s t space
d i s tan c e space o f space d i s t i n c t space v i s i o n space i. e space 25 space c m space
A s space f o c a l space l e n g t h space d e c r e a s e s comma space p o w e r space o f space l e n s space i n c r e a s e s. space
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