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CBSE Class 12-science Answered

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Asked by samisiddiqui013 | 29 May, 2021, 07:49: PM
answered-by-expert Expert Answer
Area can be calculated by-
 
A equals πr squared
straight A equals 3.14 left parenthesis 0.5 right parenthesis squared space cm to the power of 2 end exponent space equals 0.785 space cm squared
straight l equals 50 space cm


Resistance equals straight R equals ρl over straight A
straight rho equals RA over straight l
straight rho equals fraction numerator 5.5 cross times 10 to the power of negative 3 end exponent cross times 0.785 over denominator 50 end fraction equals 87.135 space Ohm minus Cm

Conductivity equals straight k equals 1 over straight rho equals fraction numerator 1 over denominator 87.35 end fraction space straight S space cm to the power of negative 1 end exponent
space space space space space space space space space space space space space space space space space space space space straight k equals 0.01148 space straight S space cm to the power of negative 1 end exponent

Molar space Conductivity left parenthesis logical and subscript straight m right parenthesis equals fraction numerator straight k cross times 1000 over denominator straight C end fraction equals fraction numerator 0.01148 cross times 1000 over denominator 0.05 end fraction equals 229.6 space straight S space cm squared space mol to the power of negative 1 end exponent
Answered by Ravi | 31 May, 2021, 11:07: AM
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