Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

yfh
Asked by manveerajput | 29 Aug, 2020, 02:14: PM
Expert Answer
To Calculate molar conductivity at infinity dilution of NH4OH, We'll use kohlrausch's law-
logical and subscript NH subscript 4 OH end subscript superscript straight o space equals logical and subscript NH subscript 4 Cl end subscript superscript straight o space plus logical and subscript NH subscript 4 OH end subscript superscript straight o space minus logical and subscript NaCl superscript straight o
logical and subscript NH subscript 4 OH end subscript superscript straight o equals space 129.8 plus 218.4 minus 108.9
logical and subscript NH subscript 4 OH end subscript superscript straight o equals space 239.9 space Scm squared mol to the power of negative 1 end exponent

Molar space conductivity

logical and subscript NH subscript 4 OH end subscript superscript straight m space equals space 9.33 space straight S space Cm squared mol to the power of negative 1 end exponent

straight alpha equals fraction numerator logical and subscript NH subscript 4 OH end subscript superscript straight m over denominator logical and subscript NH subscript 4 OH end subscript superscript straight o end fraction equals fraction numerator 9.33 over denominator 239.9 end fraction equals 0.03915

in space percent sign comma space straight alpha equals 3.915 space percent sign space
Answered by Ravi | 02 Sep, 2020, 04:28: PM
CBSE 12-science - Chemistry
Asked by eyemunshah | 20 Nov, 2021, 11:19: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by samisiddiqui013 | 29 May, 2021, 07:49: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
yfh
Asked by manveerajput | 29 Aug, 2020, 02:14: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by rakeshraghav33 | 26 May, 2018, 05:06: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Topperlearning User | 16 Jun, 2014, 10:56: AM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×