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CBSE Class 9 Answered

fourth equation of motion with respect to distance and time  
Asked by bymks.220 | 15 Mar, 2019, 18:47: PM
answered-by-expert Expert Answer
It's given as
s = u×t + 1/2 a×t^2
Where s is the distance/displacement
u is initial velocity
a is acceleration
t is time taken.
Answered by Ankit K | 15 Mar, 2019, 19:12: PM

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