CBSE Class 10 Answered
For what value of k ,k+2,4k-6,3k-2 are three consecutive trems of an ap
Asked by mdraishbst | 19 Oct, 2018, 00:18: AM
Expert Answer
Here a1 = k + 2, a2 = 4k - 6 , a3 = 3k - 2 are three consecutive terms of an A.P.
Therefore a2 - a1 = a3 - a2
4k - 6 - (k + 2) = 3k - 2 - (4k - 6)
After solving, we get
k = 3
Answered by Yasmeen Khan | 19 Oct, 2018, 10:35: AM
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