For a polyatomic gas, how is cv (specific heat at constant volume) = 4 + degree of freedom and cp(specific heat at constant pressure) = 4 + degree of freedom
Asked by Avijit Gupta | 13th Feb, 2012, 08:15: PM
Actually every degree of freedom contributes 1/2 kB T energy.
One mole of a gas has U=(3/2 kB T+ 3/2 kB T+ f kB T) NA
3/2 kB T--Due to three translational degree of freedoms.
3/2 kB T---Due to three rotational degree of freedom.
f-- No of vibrationals mode.
f kB T--Due to f vibrational degree of freedoms.
Cv=dU/dt= (3+f) R ( kB NA=R)
Cp= (4+f) R
Answered by | 14th Feb, 2012, 08:01: PM
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