Find the volume of oxygen at STP required for the complete combustion of 2 litres of carbon monoxide at S.T.P.

 

Asked by palshivom72 | 14th Jul, 2020, 07:56: PM

Expert Answer:

Combustion of Carbon monooxide-
CO space plus space 1 half straight O subscript 2 space rightwards arrow CO subscript 2

22.4 space straight L space CO space have equals space 1 space mole space of space CO
So comma space 1 space straight L space of space CO space will space have equals fraction numerator 1 over denominator 22.4 end fraction space moles space of space CO
2 space straight L space of space CO space will space have equals fraction numerator 1 over denominator 22.4 end fraction cross times 2 equals fraction numerator 1 over denominator 11.2 end fraction space moles space of space CO

According space to space stoicchiometry comma
1 divided by 2 space mole space of space straight O subscript 2 space reacts space with space 1 space mole space of space CO
So comma space For space fraction numerator 1 over denominator 11.2 end fraction space moles space of space CO comma space fraction numerator 1 over denominator 2 cross times 11.2 end fraction space moles space of space straight O subscript 2 space will space react.
Volume space of space straight O subscript 2 space equals fraction numerator 1 over denominator 2 cross times 11.2 end fraction cross times 22.4 equals 1 space straight L space

Answered by Ravi | 16th Jul, 2020, 11:21: AM