CBSE Class 10 Answered
Find the value of X for AP 1+6+11+16+...+X=148
Asked by 9452neetu | 29 Jan, 2019, 20:20: PM
Expert Answer
Let x be the n-th term of A.P.
Given : first term 1, common difference = 5, Sum of n terms 148.
Hence we have, (n/2) [ 2+(n-1)5 ] = 148
above eqn. is simplified as, 5n2 -3n -296 = 0
By factorising LHS, we write, (n-8)(5n+37) = 0
hence n, number of terms in A.P. = 8
x = 8th term = 1+(7)5 = 36
Answered by Thiyagarajan K | 29 Jan, 2019, 22:00: PM
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