Find the thickness of the plate and the wavelength of the incident light.

Asked by devjuly | 9th Jun, 2011, 09:02: PM

Expert Answer:

fringe width = lamda D/d
lamda = (0.25X 10-3 )d
 
dnew = d+ 1.2 X 10 -3
New fringe width = 2lamda/3d = lamda/(d+ 1.25 X 10-3)
 
Now can solve for lamda and d

Answered by  | 15th Jun, 2011, 01:22: PM

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