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Asked by balwansungh111334 | 13 Jul, 2022, 07:34: AM
Resultant intensity IR of two waves of radiation of intensities I1 and I2 is given as

.............................(1)
where  is intensity of radiation of source P , is intensity of radiation of source Q and  is phase difference between sources
At point A , radiation from source P has path difference 5m compare to radiation from source Q.

Phase difference for 5 m path difference = (5/20)2π = π/2

Since radiation from source P is ahead of source Q by phase (π/2) , additional phase lag (π/2) of source P due to path difference
makes the two sources in phase at point A.

Hence if we substitute  = 0 in eqn.(1), we get
.................................(2)
At point B , there is no path difference for radiations from source P and source Q.
But initially source P is ahead of source Q by phase (π/2)

Hence if we substitute  = (π/2) in eqn.(1), we get
.........................................(3)

Since initially source P is ahead of source Q by phase (π/2), total phase difference becomes π .

Hence if we substitute  = π in eqn.(1), we get
............................(4)
If two sources have same intensity , then
Hence using eqn.(2) , eqn.(3) and eqn.(4) , we get the ratio of intensities as

Answered by Thiyagarajan K | 13 Jul, 2022, 09:21: AM
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