CBSE Class 11-science Answered
Find the potential energy of a system of four particles placed at the vertices of a square of side l. Also obtain the potential at the centre of the square.
Asked by varakalasuchi3 | 26 Oct, 2018, 09:03: PM
Expert Answer
It is assumed that this question is about potential energy in gravitational field.
potential energy of a mass m in gravitational field = G×M×m/(R+h)..................(1)
Where G is gravitational constant, M is mass of earth, R is radius of earth,
h is the height above the earth's surface where the given mass m is placed.
By using the expression (1), Potential energy E of the system of 4 particles each of mass m placed
at the corner of a square of side l is given by
E = G×M×m× { [ (2/(R+h) ] +[ 2/(R+l+h) ] } ....................(2)
where h is the height above earth surface where the given square is placed, as shown in figure
If a particle of mass m is placed at centre of square its potential energy = (G×M×m) / (R+h+0.5×l)
Answered by Thiyagarajan K | 27 Oct, 2018, 01:46: AM
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