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CBSE Class 12-science Answered

Find the equation of the plane is . Find the perpendicular distance of the plane from the origin.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

The given equation of the plane is .

Here,
Perpendicular distance of the plane from the origin is
units.
 
 
Answered by | 04 Jun, 2014, 03:23: PM

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CBSE 12-science - Maths
Q 48
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CBSE 12-science - Maths
If  is the normal from the origin to the plane, and  is the unit vector along . P(x, y, z) be any point on the plane and  is perpendicular to . Find the equation of plane in the normal form.
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CBSE 12-science - Maths
Let  be the vector normal to the plane and  be the position vector of the point through which the plane passes. Then find the equation of plane.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the equation of the plane, which is at a distance of 5 unit from the origin and has as a normal vector.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the equation of the plane whose distance from the origin is 8 units and the direction ratios of the normal are 6, – 3, – 2.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the equation of the plane is . Find the perpendicular distance of the plane from the origin.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Write the normal and Cartesian form of the plane .
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the equation of the plane passing through the points (–1, 4, – 3), (3, 2, – 5) and (– 3, 8, – 5).
Asked by Topperlearning User | 26 Feb, 2015, 10:50: AM
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CBSE 12-science - Maths
Find the equation of the plane passing through the point (3, – 3, 1) and perpendicular to the line joining the points (3, 4, – 1) and (2, – 1, 5).
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CBSE 12-science - Maths
Find the co-ordinates of the foot of the perpendicular drawn from the origin to the plane 2x – 3y + 6z + 7 = 0.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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