Find the equation of the plane whose distance from the origin is 8 units and the direction ratios of the normal are 6, – 3, – 2.

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

Here, p = 8, a = 6, b = – 3, c = – 2.

Therefore, the required equation of the plane is:

Answered by  | 4th Jun, 2014, 03:23: PM