Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

explain why a ray of light passing through the centre of curvature of a concave mirror gets reflected along the same path ?
Asked by bhavikabhatia1125 | 27 May, 2021, 06:53: PM
answered-by-expert Expert Answer
As shown in figure the line passing through centre of curvature is normal to the spherical surface.
 
Hence Light ray passing through centre of curvature makes normal incidence on reflective surface of spherical mirror.
 
Hence light ray passing through centre of curvature is reflected along same path.
Answered by Thiyagarajan K | 27 May, 2021, 08:22: PM

Application Videos

Concept Videos

Multiple Choice Questions Practice Test Subjective Questions Webinar Subjective Questions Pre Board Assessment
Answered Unanswered My Questions My Answers
CBSE 10 - Physics
CASE STUDY : Light is a form of energy which induced sensation of vision to our eyes. It becomes visible when it bounces off on surface and hits our eyes. Regular reflection takes place through a smooth polished surface. The mirror outside the driver side of the vehicle is usually a spherical mirror and printed on such mirror is usually the warning "Vehicles in this mirror are closer than they appear". (i) What is the reason for this warning written on the mirror ? (ii) Draw a ray diagram showing the image formation in such kind of mirror. (iii) State two positions in which a concave mirror produces a magnified image of a given object. (iv) How is linear magnification it related to object distance and image distance ?
Asked by susrisangita792 | 23 Jul, 2023, 09:13: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
A student has focussed the image of an object of height 3 cm on a white screen using a concave mirror of focal length 12 cm. If the distance of the object from the mirror is 18 cm, find the values of the following: Distance of the image from the mirror;  Height of the image. Please answer these questions.
Asked by jayeshsah1995 | 04 Mar, 2023, 06:33: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
It is desired to obtain an erect image of an object, using concave mirror of focal length of 15 cm. Where should we place the object? Where will the image of this object be, if it is placed at 30 cm in front of the mirror? Draw a ray diagram for this situation also to justify your answer.
Asked by malikanushka07 | 17 Jun, 2022, 02:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
the question which i had asked regarding a ray of light incident perpendicularly from top of an object , is there in the cbse sample qp of 2021 but the answer given there is centre of curvature but the answer given by topperlearning is Focus, can you pls recheck
Asked by Trisha Gupta | 20 Nov, 2021, 03:30: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
what is the correct answer with explanation
question image
Asked by Trisha Gupta | 14 Nov, 2021, 01:14: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
The image formed by a concave mirror is observed to be virtual, erect and larger than the object. where should be the position of the object?
Asked by gsonal11 | 20 Sep, 2021, 02:39: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Mam what is the paraxial rays?
Asked by masterprathamesh421 | 02 Jul, 2021, 06:27: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
if an image formed an a concave mirror is real and enlarged its magnification will be
Asked by purnimap035 | 27 May, 2021, 07:56: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
explain why a ray of light passing through the centre of curvature of a concave mirror gets reflected along the same path ?
Asked by bhavikabhatia1125 | 27 May, 2021, 06:53: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
 An object of size 5 cm is placed at a distance of 20cm in front of concave mirror of radius of curvature 30cm. a) Find the position of the image, its nature and size.  b) Draw the corresponding ray diagram. 
Asked by sayantansaha225 | 26 May, 2021, 05:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt

Be a Top Scorer in the Exam with Test Series and Test Generator!

Enrol Now
×