EFor what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P?

Asked by poojakanchan | 10th Mar, 2021, 11:38: AM

Expert Answer:

k + 9, 2k – 1 and 2k + 7 are in A.P.
 
→ (2k - 1) - (k + 9) = (2k + 7) - (2k - 1) = d = common difference
→  2k - 1 - k - 9 = 2k + 7 - 2k + 1
→    k - 10 = 8
→    k  = 18

Answered by Yasmeen Khan | 10th Mar, 2021, 11:56: AM