EFor what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P?
Asked by poojakanchan | 10th Mar, 2021, 11:38: AM
k + 9, 2k – 1 and 2k + 7 are in A.P.
→ (2k - 1) - (k + 9) = (2k + 7) - (2k - 1) = d = common difference
→ 2k - 1 - k - 9 = 2k + 7 - 2k + 1
→ k - 10 = 8
→ k = 18
Answered by Yasmeen Khan | 10th Mar, 2021, 11:56: AM
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