Divide a line segment of length 8 cm in the ratio 3:2.

### Asked by Topperlearning User | 13th Dec, 2013, 02:59: AM

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Steps of construction.

Steps of construction.

i. Draw a line segment AB = 8 cm.

ii. Draw any ray making an acute angle BAX with AB.

iii. Along AX mark 5 (3 +2) points A_{1}, A_{2}, A_{3}, A_{4} and A_{5} such that AA_{1} = A_{1}A_{2} = A_{2}A_{3} = A_{3}A_{4} = A_{4}A_{5}.

iv. Join BA_{5}

v. Through A_{3} draw a line A_{3}P parallel to A_{5}B by making an angle equal to AA_{5}B at A_{3} intersecting AB at point P.

The point P so obtained is the required point, which divides AB internally in the ratio 3: 2

### Answered by | 13th Dec, 2013, 04:59: AM

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