CBSE Class 10 Answered
Steps of construction;
i. Draw BC = 6cm
ii. At B construct angle CBX = 50o
iii. At C construct angle BCY = 60o
iv. Let BX and CY intersect at A. Triangle ABC thus obtained is the given triangle.
v. Construct an acute angle CBZ at B on opposite side of the vertex A of triangle ABC.
vi. Mark off 3 (greater 3 in 2/3) points B1, B2, B3 on BZ such that BB1 = B1B2 = B2B3.
vii. Join B3 to C and draw a line through B2 parallel to B3C, intersecting BC at P.
viii. Through P draw PQ parallel to AC, meeting AB at Q
ix. BPQ is the required triangle, each of whose sides is two-thirds of the corresponding sides of triangle ABC.
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