CBSE Class 10 Answered

i. Draw BC = 6cm

ii. At B construct angle CBX = 50^o

iii. At C construct angle BCY = 60^o

iv. Let BX and CY intersect at A. Triangle ABC thus obtained is the given triangle.

v. Construct an acute angle CBZ at B on opposite side of the vertex A of triangle ABC.

vi. Mark off 3 (greater 3 in 2/3) points B_1, B_2, B₃ on BZ such that BB₁ = B₁B₂ = B₂B₃.

vii. Join B₃ to C and draw a line through B₂ parallel to B₃C, intersecting BC at P.

viii. Through P draw PQ parallel to AC, meeting AB at Q

ix. BPQ is the required triangle, each of whose sides is two-thirds of the corresponding sides of triangle ABC.