Divide 32 into 4 parts such that all are in A.P such that the ratio of product of extremes to the p
Asked by | 23rd Feb, 2008, 06:33: PM
Your question was
Divide 32 into 4 parts such that all are in A.P such that the ratio of product of extremes to the product of means is 7: 15.
Let us take the 4 numbers in AP as a-3d,a-d,a+d,a+3d
Now a-3d+a-d+a+d+a+3d = 32
So 4a = 32
a = 8
Also According to II condition
(a2 -9d2):(a2-d2) =7:15
So 15( a2 -9d2) = 7(a2-d2)
15(64 - 9d2) = 7(64-d2)
Solving we get d = 2
So the AP is 2,6,10,14 or 14,10,6,2
Answered by | 5th Dec, 2017, 06:01: PM
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