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CBSE Class 11-science Answered

dimensional analysis
Asked by sjrocks15 | 20 Apr, 2010, 11:49: PM
Expert Answer

The description can be written compactly as,

F μa Rb Vc , where symbols have their usual meaning.  ............(1)

The dimensions are,

F = [MLT-2]

μ  =[ML-1T-1]

R = [L]

V = [LT-1]

Using these dimensions in (1),

[MLT-2] = [ML-1T-1]a [L]b [LT-1]c

Comparing dimensions of M:

1 = a

Comparing dimensions of L:

1 = - a + b +c

b+c = 2          .. since a = 1,

Comparing dimensions of T:

-2 = -a -c

c = 1,

Hence b = 1.

Therefore the relation is,

μ R V ,

F = C μ R V .

where C is some constant.

regards,

Team,

TopperLearning.

 

Answered by | 21 Apr, 2010, 09:50: AM

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