CBSE Class 12-science Answered
determine the amt og cacl2 with i=2.47 dissolved in 2.5l water so that its oxmotic pressure is 0.75atm in 27 degree celsius
Asked by Akshaya Parthasarathy | 10 Jul, 2011, 12:00: AM
Expert Answer
Given i = 2.47
Now,
= i x CRT
= i nBRT /V
0.75 =2.47 X nB 0.082 X300/2.5
nB= 0.75 X 2.5 /2.47 X0.082 X 300
= 0.03 mol
Therefore amount of CaCl2 dissolved =0.03 x 111 =3.33 g
Answered by | 11 Jul, 2011, 10:06: AM
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