determine the amt og cacl2 with i=2.47 dissolved in 2.5l water so that its oxmotic pressure is 0.75atm in 27 degree celsius

Asked by Akshaya Parthasarathy | 10th Jul, 2011, 12:00: AM

Expert Answer:

 Given   i = 2.47
Now, 

 =   i  x CRT

   = i nBRT /V

    0.75 =2.47 X nB 0.082 X300/2.5

nB= 0.75 X 2.5 /2.47 X0.082 X 300

    = 0.03 mol

Therefore amount of CaCl2 dissolved =0.03 x 111 =3.33 g

Answered by  | 11th Jul, 2011, 10:06: AM

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