# CBSE Class 10 Answered

**Define: a) Diffraction b) Relation between focal length and radius of curvature and also proof it? c) between which two points related to a concave mirror ,should an object be placed to obtain on a screen an image twice the size of the object d) lateral displacements and its calculation.**

The relationship between the focal length f and radius of curvature r is r = 2f.

Consider a ray of light AB, parallel to the principal axis and incident on a spherical mirror at point B. The normal to the surface at point B is CB and CP = CB = R, is the radius of curvature. The ray AB, after reflection from mirror, will pass through F (concave mirror) or will appear to diverge from F (convex mirror) and obeys the law of reflection i.e. i = r.

From the geometry of the figure,

∠BCP = θ = i

In D CBF, θ = r

∴BF = FC (because i = r)

If the aperture of the mirror is small, B lies close to P, and therefore BF = PF

Or FC = FP = PF

Or PC = PF + FC = PF + PF

Or R = 2 PF = 2f

Or f = R/2

Similar relation holds for convex mirror also. In deriving this relation, we have assumed that the aperture of the mirror is small.

c) object must be placed between C and FA ray of light travels in a certain straight line path. After refraction through a glass slab, it emerges in a direction parallel to the original direction but slightly displaced from the line. This is called the lateral displacement.