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cosA - sinA+1/ cosA+sinA-1 = cosecA+ cotA Solve the above.

Asked by roysubarna2016 | 02 Oct, 2018, 11:27: AM

Expert Answer

begin mathsize 16px style straight L. straight H. straight S space equals space fraction numerator cosA space minus space sinA space plus space 1 over denominator cosA space plus space sinA space minus space 1 end fraction Divide space and space Multiply space by space sinA space equals space fraction numerator sin straight A space left parenthesis cosA space minus space sinA space plus space 1 right parenthesis over denominator sin straight A space left parenthesis cosA space plus space sinA space minus space 1 right parenthesis end fraction space equals space fraction numerator sinAcosA space minus space sin squared straight A space plus space sinA over denominator sinA left parenthesis cosA space plus space sinA space minus space 1 right parenthesis end fraction equals fraction numerator sinAcosA space plus space sinA space minus space left parenthesis 1 space minus space cos squared straight A right parenthesis over denominator sinA left parenthesis cosA space plus space sinA space minus space 1 right parenthesis end fraction equals fraction numerator sinA left parenthesis cosA space plus space 1 right parenthesis space minus space left parenthesis 1 space minus space cosA right parenthesis left parenthesis 1 space plus space cosA right parenthesis over denominator sinA left parenthesis cosA space plus space sinA space minus space 1 right parenthesis end fraction equals fraction numerator left parenthesis 1 space plus space cosA right parenthesis space left parenthesis sinA space plus space cosA space minus space 1 right parenthesis over denominator sinA left parenthesis cosA space plus space sinA space minus space 1 right parenthesis end fraction equals fraction numerator 1 space plus space cosA over denominator sinA end fraction equals 1 over sinA space plus space cosA over sinA equals cosecA space plus space cotA equals straight R. straight H. straight S end style

Answered by Yasmeen Khan | 03 Oct, 2018, 12:15: PM

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