CBSE Class 8 Answered
Construct a parallelogram with 5.2cm and 4.7cm as lengths of adjacent sides and 7.6cm as the length of the diagonal connecting these given sides. Also, write the steps of construction.
Let the required ||gm be EFGH with EF = 5.2cm and FG =4.7cm and EG = 7.6cm.
Steps of Construction:
a)Draw EF = 5.2cm.
b)With E is centre and radius 7.6cm, draw an arc.
c)With F as centre and radius 4.7cm, draw another arc which cuts arc of step (b) at point G.
d)Join EG and FG.
e)With G as centre and radius 5.2cm, draw an arc.
f)With E as centre and radius 4.7cm, draw another arc which intersects the arc drawn in step (e) at H.
g)Join HG and HE.
EFGH is the required parallelogram.