CBSE Class 8 Answered

Let the required ||gm be EFGH with EF = 5.2cm and FG =4.7cm and EG = 7.6cm.

Steps of Construction:

a)Draw EF = 5.2cm.

b)With E is centre  and radius 7.6cm, draw an arc.

c)With F as centre and radius 4.7cm, draw another arc which cuts arc of step (b) at point G.

d)Join EG and FG.

e)With G as centre and radius 5.2cm, draw an arc.

f)With E as centre and radius 4.7cm, draw another arc which intersects the arc drawn in step (e) at H.

g)Join HG and HE.

EFGH is the required parallelogram.