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Consider 4 forces:
vector A: 3N, 26° East of North
vector B: 5N, 11° West of North
vector C: 5/√2 N, 34° West of South
vector D: 4N, 64° East of South
Then the magnitude of vector A + vector B + vector C + vector D is
Asked by sd8022567 | 09 Jun, 2022, 12:53: PM
Expert Answer
Let and are unit vectors along +x axis and +y axis respectively
Magnitude of above resultant vector is calculated as
If direction of makes angle θ , then tanθ = 2.920 / 1.979 = 1.475 , hence θ = tan-1 (1.475 ) = 56o
Above resultant vector can be written as
Hence resultant vector is of magnitude 3.527 N and direction is 56o North of East
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