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10meast 12m north 4m south 4m West find the displacement
Asked by anjjuchalla7 | 28 Oct, 2023, 08:31: PM
Expert Answer
Graphical method :-
Above graph shows Displacements made at different direction.
Initially the object is at A . First displacement AB of magnitude 10 m is made towards East .
Then BC of magnitude 12 m is made towards north. Nex displacement is CD of magnitude 4 m towards south.
Final displacement is DE of magnitude 4 m towards west .
Net displacement from starting position to final position is AE . If we measure the magnitude of AE ,
we find that net displacement AE is of magnitude 10 m .
If we measure the direction angle θ from graph ,
we find that tanθ = 8/6 or θ = tan-1 ( 4/3 ) = 53o
Hence the net displacement is 10 m in the direction 53o north of east
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Vector method :-
Let direction towards East is the direction of x-axis . Let direction towards north is direction of y-axis as shown in figure.
Let be the unit vector along x-axis and be the unit vector along y-axis .
Displacement AB = ;
Displacement BC = ;
Displacement CD =
Displacement DE =
Net displacement = =
magnitude of =
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