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boy a is standing at a point 3 m west and 4 m south to boy b. assume the east and the north towards the positive x and y axis of coordinate system. boy a starts moving along a vector a =1.5 i +2 j with a constant speed of 2m/s for 5 seconds and stops. now how far is the boy a from the boy b
Asked by nutankumari95074 | 12 Jun, 2022, 13:28: PM
Expert Answer
Let us consider boy B is standing at origin . Initially boy-A is 3 m west and 4 m south .
hence initial coordinate of boy-A = ( -3 m , -4 m )
Boy-A is travelling in the direction of vector v = ( 1.5 i + 2.0 j )
Unit vector 
along the direction of vector v is given as
along the direction of vector v is given as 
If boy-A travels with speed 2 m/s for 5 s , then magnitude of displacement 10 m
Displacement vector from initial position of boy-A = 10 ( 0.6 i + 0.8 j ) m = ( 6 i + 8 j ) m
Hence boy-A has diplaced 6 m towards east and 8 m towards north.
Hence final coordinates of boy-A = ( -3+6 m , -4+8 m ) = ( 3m , 4 m )
Distance between boy-A and boy-B = 
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