Compare the rate of nitration under similar conditions of Ph-O-Me and Ph-S-Me. Explain
Asked by Topperlearning User | 1st Jun, 2016, 02:54: PM
PhOMe>PhSMe . The ∏ bond from O (which uses a 2p orbital) to the ring Carbon is shorter and stronger than the comparable bond from S (which uses a 3p orbital) to the ring Carbon and -OCH3 being an activating group has higher rate of nitration.
Answered by | 1st Jun, 2016, 04:54: PM
- Ch3 ch2 cl
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