Compare the rate of nitration under similar conditions of Ph-O-Me and Ph-S-Me. Explain

Asked by Topperlearning User | 1st Jun, 2016, 02:54: PM

Expert Answer:

PhOMe>PhSMe . The ∏ bond from O (which uses a 2p orbital) to the ring Carbon is shorter and stronger than the comparable bond from S (which uses a 3p orbital) to the ring Carbon and -OCH3 being an activating group has higher rate of nitration.

Answered by  | 1st Jun, 2016, 04:54: PM