calculate

Asked by  | 25th Aug, 2008, 11:25: PM

Expert Answer:

Let volume  of O2 = x ml
hence volume of O3 = 600 - x ml
at NTP,
wt of x ml O2 = 32*x/22400 gm
wt of 600 - x ml O3 = 48*(600 - x)/22400 gm

hence,
32*x/22400 + 48*(600 - x)/22400 = 1
or, 32x + 28800 - 48x = 22400
=> 16x = 28800 - 22400 = 6400
=> x = 6400/16 = 400 ml

so vol of O2 in the mixture is 400 ml.

SO , the volume of O3 =, 600- 400

                                   = 200ml

Answered by  | 20th Oct, 2008, 02:09: PM

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