Calculate weight in gram, number of moles and number of molecules in 1120 cm^3 of N2(Nitrogen gas) at S.T.P. (Take Avogadro number 6 x 10^23).

Asked by dr_pradip27121972 | 25th Mar, 2018, 03:38: PM

Expert Answer:

 
Given colon

straight N subscript 2 space equals space 1120 space cc

We space know space that comma

22400 space cc space equals space 1 space mole space

therefore space 1120 space cc space equals space fraction numerator 1120 cross times 1 over denominator 22400 end fraction

space space space space space space space space space space straight N subscript 2 space space space space space equals space 0.05 space mole

1 space mole space contains space 6.022 cross times 10 to the power of 23 space molecules
0.05 space mole space will space contain comma space space space
space equals space 6.022 cross times 10 to the power of 23 space cross times 0.05

equals space 3.0 cross times 10 to the power of 22 space molecules

1 space mole space of space space straight N subscript 2 space equals space 28 space straight g

therefore space 0.05 space mole space equals space space 28 cross times 0.05

space space space space space space space space space space space space space space space space space space space space space space equals 1.4 space gm
 
Weight of N2 = 1.4 gm
No.of molecules = 3 ×1022 
Moles of N2 = 0.05 mol

Answered by Varsha | 26th Mar, 2018, 06:20: PM