Calculate the no. Of particles present in 444g of calcium chloride?

Asked by nisha_vini29 | 13th Nov, 2017, 12:13: PM

Expert Answer:

No. space of space p a r t i c l e s space in space 444 space straight g space of space CaCl subscript 2 space
No. space of space moles equals 444 over 111
space space space space space space space space space space space space space space space space space space space equals 4
1 space mole space of space substance space contains space 6.022 cross times 10 to the power of 23 space particles comma space
therefore 4 cross times space 6.022 cross times 10 to the power of 23 equals 2.40 cross times 10 to the power of 24
As space one space CaCl subscript 2 space unit space contains space 2 space Cl space therefor comma
2.40 cross times 10 to the power of 24 cross times 2 equals 4.81 cross times 10 to the power of 24 space particles

Answered by Varsha | 13th Nov, 2017, 12:57: PM