Calculate the molality and molarity of a 15%solution (by weight) of sulphuric acid of density 3 1.020gcm . (Atomic masses: H = 1, O =16, S = 32 amu)

Asked by mohitgehlot | 3rd Mar, 2011, 06:52: AM

Expert Answer:

Volume of 100 g the solution  = 100/31.020= 3.22  l
molarity = 15/98 x 3.22
             =.0475 mol/l
molality = .153 / .085 = 1.8 mol /kg

Answered by  | 3rd Mar, 2011, 11:27: AM

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