Calculate the magnetic field produced at the center of hydrogen atom due to orbital motion of electron in clockwise direction.

Asked by j4jaigupta1998 | 13th Jun, 2015, 07:37: AM

Expert Answer:

begin mathsize 12px style When space an space electron space moving space in space straight a space circular space orbit space its space magnetic space field space is space given space as comma straight B equals fraction numerator straight mu subscript 0 straight I over denominator 2 straight R end fraction space space space space space space left parenthesis 1 right parenthesis straight I space is space the space current space through space the space circular space loop. straight R space is space the space radius space of space hydrogen space orbit. straight mu subscript 0 space the space magnetic space permeablity space of space free space space. The space radius space of space hydrogen space orbit space is space given space as comma straight R equals fraction numerator straight n squared straight h squared over denominator 4 straight pi squared mZe squared end fraction space space space space space space space left parenthesis 2 right parenthesis straight Z space is space the space atomic space number straight e space is space charge straight m space is space the space mass space of space electron straight h space is space Plank apostrophe straight s space no Substituting space left parenthesis 2 right parenthesis space in space left parenthesis 1 right parenthesis space we space get comma straight B equals fraction numerator straight mu subscript 0 straight I over denominator 2 end fraction open parentheses fraction numerator 4 straight pi squared mZe squared over denominator straight n squared straight h squared end fraction close parentheses end style

Answered by Priyanka Kumbhar | 14th Jun, 2015, 07:38: PM

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