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How much energy is stored in a 3 cm diameter, 12 cm long solenoid that has 200 turns of wire and carries a current of 0.8A?
Asked by arjunsah797 | 26 Mar, 2022, 09:10: AM
Energy U stored per unit volume in magnetic field  is given as

U = (1/2) ( B2 / μo )....................... (1)

where B is magnetic field induction and μo is permeability of free space

Magnetic field induction B in solenoid is given as

B = μo ( N / L ) I ..............................(2)

where N is number of turns, L is length of solenoid and I is current passing through solenoid

Using eqn.(2) , we get energy U stored per unit volume from eqn.(1) as

U = (1/2) μo ( N / L )2 I2

Energy E stored in solenoid is obtained by multiplying above expression by volume ( A × L ) of solenoid ,
where A is crosssection area of solenoid .

E = [ (1/2) μo ( N / L )2 I2 ] × ( A × L )

By substituting values in above expression , we get E = 9.5 × 10-5 J

Answered by Thiyagarajan K | 26 Mar, 2022, 12:11: PM

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